Question

a horizontal force pulls a 40- kg bag of fertilizer across the floor. what is the minimum force required if the coefficient of friction is 0.36?

Answer 1

Step-by-step explanation:

You must overcome the force of friction for the bag to move

Normal force = mg = 40 * 9.81 =392.4 N

Normal force * coefficient = force of friction = 392.4 * .36 = 141.3 N