Final answer:
To find the number of moles of AgNO3 present in 50 mL of a 0.250 M solution, we can use the formula n = M x V, where n is the number of moles, M is the molarity, and V is the volume in liters. So, the number of moles of AgNO3 in 50 mL is 0.0125 moles.
Step-by-step explanation:
To find the number of moles of AgNO3 present in 50 mL of a 0.250 M solution, we can use the formula:
n = M imes V
where n is the number of moles, M is the molarity, and V is the volume in liters. So, the number of moles of AgNO3 in 50 mL is:
n = 0.250 mol/L imes 0.050 L = 0.0125 moles