We are given the following information:Let ƒ be a function which has an inverse and let f(−1) = 2. If Q is the surface of revolution obtained when x = f(z) is revolved about the x-axis, we are supposed to determine if the point (2, -1, 3) is on Q.Let's solve this problem below:Since f(x) is revolved around x-axis, we can use the formula of a surface of revolution around the x-axis that is given as:^2 + ^2 = (())^2If x = f(z), then f(−1) = 2, hence (−1) = 2.Now we have two equations that we can substitute x and y values in.^2 + ^2 = (())^2 ———- Equation 1.(−1) = 2 ———- Equation 2.x = f(z) = 2. We get that y = -1, z = 3.Substituting the values into the first equation, we get: ^2 + ^2 = (())^2 = (f(2))^2 = 4.^2 + ^2 = 4Squaring both sides:^2 + ^2 - 4 = 0We can see that the given point (2, -1, 3) satisfies the above equation. Hence the point is on the surface of revolution Q. Answer: Yes, the point (2,-1,3) is on Q.