Question

Use the distributive property to write an equivalent expression

1. 5(x + y)
2. a(b + c)
3. 3(2u + v)
Factor
4. 7a + 7b
5. 14c + 21d
6. ax + ay + az

Answer 1

Answer:
1. 5x + 5y
2. ab + ac
3. 64 + 3v
4.7 (a+ b)
5.7(2c + 3d)
6. a (x+ y +z)
Explanation:
1-3:
Using the distributive property we get these answers.
4:
The common term between 7a and 7b is 7, so we write 7 (a + b)
5:
The common term is 7 again, as 14 and 21 are both divisible by it.
6:
The common term is a.

Answer 2

1. 5x + 5y

2. ab + ac

3. 6u + 3v

4. 7 ( a + b )

5. 7 ( 2c + 3d )

6. a ( x + y +z )

Explanation:

1-3:

Using the distributive property we get these answers.

4:

The common term between 7a and 7b is 7, so we write 7 ( a + b )

5:

The common term is 7 again, as 14 and 21 are both divisible by it.

6:

The common term is a.