Question

For field day, Mrs. Douglas puts students into teams. There are 48 boys and 64 girls. Each team must have the same number of boys and the same number of girls. All students must participate. What is the greatest number of teams Mrs. Douglas can create?

Answer 1

To form teams with the same number of boys and girls, we need to find the greatest common factor (GCF) of 48 and 64.

We can start by finding the prime factorization of each number:

48 = 2 * 2 * 2 * 2 * 3

64 = 2 * 2 * 2 * 2 * 2 * 2

The GCF is found by taking the product of all the common factors raised to the smallest power. In this case, the common factors are 2 raised to the fourth power (since both numbers have four 2's in their prime factorization). So the GCF is:

GCF(48, 64) = 2^4 = 16

This means that there are 16 boys and 16 girls on each team. To find how many teams can be formed, we need to divide the total number of students by the number of students per team:

Total number of students = 48 boys + 64 girls = 112 students

Number of students per team = 16 boys + 16 girls = 32 students

Number of teams = Total number of students / Number of students per team

Number of teams = 112 / 32

Number of teams ≈ 3.5

Since we cannot have a fractional number of teams, we must round down to the nearest whole number. Therefore, the greatest number of teams Mrs. Douglas can create is 3 teams. Each team will have 16 boys and 16 girls.

Answer 2

Explanation:

To determine the greatest number of teams Mrs. Douglas can create, we need to find the largest common factor of 48 (number of boys) and 64 (number of girls).

To find the greatest common factor (GCF) of 48 and 64, we can list the factors of each number and identify the largest one they have in common.

Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

Factors of 64: 1, 2, 4, 8, 16, 32, 64

The largest common factor of 48 and 64 is 16. Therefore, Mrs. Douglas can create a maximum of 16 teams, with each team consisting of 3 boys and 4 girls.