Question

titan completes one orbit about saturn in 15.9 days and the average saturn–titan distance is 1.22×109 m. calculate the angular speed of titan as it orbits saturn.

Answer 1

The angular speed of Titan as it orbits Saturn is approximately 0.0046 radians per second.

Step-by-step explanation:

The angular speed of Titan as it orbits Saturn can be calculated using the formula:

angular speed = (2π)/(orbital period)

Given that the orbital period of Titan is 15.9 days, we can convert it to seconds by multiplying it by 24 hours, 60 minutes, and 60 seconds. The result is approximately 1,373,760 seconds. Now, we can substitute this value into the formula:

angular speed = (2π)/(1,373,760 seconds)

Calculating this, we get an angular speed of approximately 0.0046 radians per second.

Answer 2

The angular speed of Titan as it orbits Saturn is 1.45 x 10^-6 rad/s.

Step-by-step explanation:

The angular speed of an object in orbit can be calculated using the formula:

Angular speed = 2π/Period

Given that the period of Titan's orbit around Saturn is 15.9 days, we can calculate the angular speed as follows:

Angular speed = 2π/15.9 days

Convert the period to seconds:

15.9 days x 24 hours/day x 60 minutes/hour x 60 seconds/minute = 1,373,760 seconds

Substitute the value into the formula:

Angular speed = 2π/1,373,760 seconds = 1.45 x 10-6 rad/s (rounded to two decimal places)