Final answer:
The resistance of the resistor in this RLC circuit can be calculated using the impedance formula and the given values of the rms voltage and inductance. The resistance is approximately 4.91 Ω.
Step-by-step explanation:
In an RLC circuit, the rms voltage across the inductor can be calculated using the formula:
VL = IL * XL
Where VL is the voltage across the inductor, IL is the current through the inductor, and XL is the reactance of the inductor. The reactance of the inductor can be calculated using the formula:
XL = 2πfL
Where f is the frequency of the generator and L is the inductance of the inductor.
In this case, the rms voltage across the inductor is given as 3.7 V and the frequency is given as 110 Hz. Plugging in these values into the formula, we can calculate XL as follows:
XL = 2π * 110 * 0.032
Simplifying, we get:
XL ≈ 21.76 Ω
Now, since the resistor and the inductor are connected in series, the total impedance of the circuit can be calculated as follows:
Z = √(R2 + XL2)
Given that the rms voltage across the generator is 7.2 V, we can also use this formula to calculate the resistance of the resistor:
R = √(Z2 - XL2)
By plugging in the values of Z and XL, we can find the resistance R:
R = √((7.22) - (21.762))
Simplifying, we get:
R ≈ 4.91 Ω
Therefore, the resistance of the resistor in this circuit is approximately 4.91 Ω.