The composite function in the form f(g(x)) is y = e^(3√(x+9)). Here, the inner function is u = g(x) = x + 9, and the outer function is y = f(u) = e^(3√u).
To find the derivative dy/dx, we can use the chain rule.
dy/dx = dy/du * du/dx
dy/du = e^(3√u) * (3/2) * (1/sqrt(u)) = (3/2) * e^(3√u) / √u
du/dx = 1
Therefore,
dy/dx = dy/du * du/dx = (3/2) * e^(3√u) / √u
Substituting u = x + 9, we get:
dy/dx = (3/2) * e^(3√(x+9)) / √(x+9)