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if 100.0 molecules of h₂ and 31.0 molecules of o₂ react, how many molecules of h₂o can be produced in the reaction below? 2 h₂(g) o₂(g) → 2 h₂o(g)

User Susilo
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2 Answers

6 votes

Final answer:

In the given reaction, for every 2 molecules of H₂ that react, 2 molecules of H₂O are produced. With 100.0 H₂ molecules and 31.0 O₂ molecules, the limiting reactant is O₂, and therefore we can produce 31.0 molecules of H₂O.

Step-by-step explanation:

In the given reaction 2 H₂(g) + O₂(g) → 2 H₂O(g), we can see that for every 2 molecules of H₂ that react, 2 molecules of H₂O are produced. Therefore, the ratio of H₂ to H₂O is 1:1.

Given that there are 100.0 H₂ molecules and 31.0 O₂ molecules, we need to determine which reactant limits the amount of product produced. Since we have more than enough H₂ (100.0 molecules) to react with the available O₂ (31.0 molecules), the limiting reactant is O₂.

Since the ratio of H₂ to H₂O is 1:1, we can conclude that 31.0 molecules of H₂O can be produced in this reaction.

User Nehemiah
by
8.3k points
1 vote

Final answer:

The maximum number of H₂O molecules that can be produced in the given reaction is 1.03 x 10^-22 molecules of H₂O.

Step-by-step explanation:

Based on the balanced chemical equation 2H₂(g) + O₂(g) → 2H₂O(g), we can determine the stoichiometric ratios to calculate the number of water molecules produced. In this reaction, 2 molecules of H₂ react with 1 molecule of O₂ to produce 2 molecules of H₂O. Given that there are 100.0 molecules of H₂ and 31.0 molecules of O₂, we can determine the limiting reactant and calculate the amount of water produced accordingly.

First, let's calculate the molar amounts of H₂ and O₂ given the number of molecules. Since 1 mole of any substance contains Avogadro's number of molecules, we can use the conversion factor:

  • 1 mole H₂ = 6.022 × 10^23 molecules of H₂

Using this conversion, we find that we have 1.66 x 10^-22 moles of H₂ and 5.15 x 10^-23 moles of O₂. Since there are 2 moles of H₂ for every mole of O₂, it is clear that O₂ is the limiting reactant. Therefore, the maximum number of H₂O molecules that can be produced is twice the number of O₂ molecules, which is 2 x 5.15 x 10^-23 = 1.03 x 10^-22 molecules of H₂O.

User Dean Clark
by
8.6k points
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