Final answer:
The maximum number of H₂O molecules that can be produced in the given reaction is 1.03 x 10^-22 molecules of H₂O.
Step-by-step explanation:
Based on the balanced chemical equation 2H₂(g) + O₂(g) → 2H₂O(g), we can determine the stoichiometric ratios to calculate the number of water molecules produced. In this reaction, 2 molecules of H₂ react with 1 molecule of O₂ to produce 2 molecules of H₂O. Given that there are 100.0 molecules of H₂ and 31.0 molecules of O₂, we can determine the limiting reactant and calculate the amount of water produced accordingly.
First, let's calculate the molar amounts of H₂ and O₂ given the number of molecules. Since 1 mole of any substance contains Avogadro's number of molecules, we can use the conversion factor:
- 1 mole H₂ = 6.022 × 10^23 molecules of H₂
Using this conversion, we find that we have 1.66 x 10^-22 moles of H₂ and 5.15 x 10^-23 moles of O₂. Since there are 2 moles of H₂ for every mole of O₂, it is clear that O₂ is the limiting reactant. Therefore, the maximum number of H₂O molecules that can be produced is twice the number of O₂ molecules, which is 2 x 5.15 x 10^-23 = 1.03 x 10^-22 molecules of H₂O.