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limit as (x to infinity) (root (x^2-20 x+3)-x) (Is LH really needed here? What value does a graph suggest?).

User Herpderp
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1 Answer

1 vote

Answer:

-10

Explanation:


\displaystyle \lim_(x\rightarrow\infty)√(x^2-20x+3)-x\\\\=\lim_(x\rightarrow\infty)√(x^2-20x+100-97)-x\\\\=\lim_(x\rightarrow\infty)√((x-10)^2-97)-x\\\\=\lim_(x\rightarrow\infty)x-10-x\\\\=-10

User Prasad Vsv
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