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Leading coefficient of F(x)=-4x^2-9x^5+7x^3+4x^4

2 Answers

6 votes

Answer:

-9

Explanation:

To solve this problem, you first need to put this problem in degree descending order.

monoidalTo do this, you first put the mononoimal with the highest exponent (The one with the most value).

This is done below:


F(x)=-4x^2-9x^5+7x^3+4x^4\\\\ - This is the original problem just rewritten


F(x)=-9x^5-4x^2+7x^3+4x^4 - You move the -9x first because it has the highest exponent of 5


F(x)=-9x^5+4x^4-4x^2+7x^3exponent - We put the 4x next because the expinet of 4 is higher than both 2 and 3


F(x)=-9x^5+4x^4+7x^3-4x^2because - Next, we put the 7x before the -4x because it has a higher exponent

After doing this, we can see that the leading monomial is
-9x^5. The leading coefficient is the number in front of the variable or, in this case, -9.

User Clive Makamara
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4 votes
The leading coefficient is -9
Leading coefficient of F(x)=-4x^2-9x^5+7x^3+4x^4-example-1
User Guillaume Polet
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