Question

Find m/JKL in OE.

A. 53°
B. 37°
C. 106°
D. 43°
L
E
74°
K

Answer 1

A

Explanation:

the inscribed angle JKL is half the measure of its intercepted arc

the sum of the arcs in a circle in a circle = 360°

since LK is a diameter the arc KL is equal to the measure of its central angle , that is

arc LK = 180° , then

LJ + JK + KL = 360°

LJ + 74° + 180° = 360°

LJ + 254° = 360° ( subtract 254° from both sides )

LJ = 106°

Then

∠ JKL =
`(1)/(2)` × 106° = 53°