Answer:
In an SN2 reaction when a methoxide ion (CH 3 O –) approaches a tetravalent carbon atom, it readily reacts. However, if tertiary butoxide ion C (CH 3) 3 O – is allowed to react with the same tetravalent carbon atom, it will face severe steric hindrance. Thus, the ability of tertiary butoxide ion to function as a nucleophile is sufficiently low.