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2 votes
How many atom and molecules of sulphur present in 64.0 g of sulphur

2 Answers

6 votes

Answer:

1.506×1023 molecules

Step-by-step explanation:

How many atoms and molecules of sulphur are present in 64.0 g of sulphur (S8)? ∴ 64 g of sulphur will contain=6.022×1023×64256=1.506×1023 molecules.

User JacopoStanchi
by
7.8k points
6 votes

Answer:

1.2046*10^24 molecules

User Nopeva
by
7.7k points

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