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What is the mass, in grams, of 1.75 x 1020 molecules of caffeine, C8H10N4O2?

User Morshed
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1 Answer

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C: 8 atoms x atomic mass of carbon (12.01 g/mol) = 96.08 g/mol

H: 10 atoms x atomic mass of hydrogen (1.01 g/mol) = 10.10 g/mol

N: 4 atoms x atomic mass of nitrogen (14.01 g/mol) = 56.04 g/mol

O: 2 atoms x atomic mass of oxygen (16.00 g/mol) = 32.00 g/mol

Adding these values together, we get:

96.08 g/mol + 10.10 g/mol + 56.04 g/mol + 32.00 g/mol = 194.22 g/mol

Therefore, the molecular mass of caffeine is approximately 194.22 g/mol.

To find the mass of 1.75 x 10^20 molecules of caffeine, we can use the following equation:

Mass = (Number of molecules) x (Molecular mass)

Mass = (1.75 x 10^20) x (194.22 g/mol)

Calculating the result:

Mass ≈ 3.40 x 10^22 g

Therefore, the mass of 1.75 x 10^20 molecules of caffeine is approximately 3.40 x 10^22 grams.
User IvanL
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