Question

Any answers for these four questions?

Answer 1

5) AB = CB = 9√2

6) JK = 3√3 LK = 6√3

7) UV = 6√3 VW = 6

8) RQ = 5√10 PQ = 10√5

Explanation:

SOH CAH TOA

5) tan 45° = 1 =
`(CB)/(AB)`

CB = AB

Sin 45° =
`(1)/(√(2) ) = (CB)/(18)\\CB = (18)/(√(2) ) \\CB = 9√(2)`

since CB = AB

∴ AB = 9√2

6) Tan 60° =
`√(3) = (9)/(JK)\\ JK = (9)/(√(3) ) \\JK = 3√(3)`

Sin 60 =
`(√(3) )/(2) = (9)/(LK)\\ LK = (18)/(√(3) ) \\LK = 6√(3)`

7) Sin 60 =
`(√(3) )/(2) = (UV)/(12)\\ UV = 6√(3)`

Cos 60 =
`(1)/(2) = (VW)/(12)\\ VW = 6`

8) Tan 45 = 1 =
`(RQ)/(5√(10) )`

RQ = 5
`\sqrt{10`

Sin 45 =
`(1)/(√(2)) = (5√(10) )/(PQ)\\ PQ = 10√(5)`