Final answer:
ANOVA and the Student’s t-test yield the same conclusions when only two treatments are involved. In this example, the F-value is calculated to be 13.2, indicating a significant difference between the two groups.
Step-by-step explanation:
When only two treatments are involved, ANOVA and the Student’s t-test result in the same conclusions. In this case, ANOVA and the t-test will yield the same result because there are only two groups being compared. The t2 = F relationship holds true when only two treatments are involved. In other words, the squared t-value is equal to the F-value.
Now let's calculate the F-value for the given example. The mean number correct for the normal lecture format group is 4,939.2 and the mean number correct for the distance format group is 2,469.6. The total variability is 3,741.6. To calculate the F-value, we use the formula F = (SSB / dfB) / (SSE / dfE), where SSB is the variation between groups, dfB is the degrees of freedom for the numerator, SSE is the variation within groups, and dfE is the degrees of freedom for the denominator. The F-distribution has 3 degrees of freedom in the numerator and 10 degrees of freedom in the denominator.
Using the given numbers, we can calculate the F-value as follows:
F = (SSB / dfB) / (SSE / dfE) = (3,741.6 / 3) / (3,741.6 / 10) = 13.2
The calculated F-value is 13.2, which indicates that there is a significant difference between the two groups.