Question

A car is traveling along a road that makes a 13° angle with the ground. Find the elevation of the car on a stretch of road that extends horizontally 125 meters. Round your answer to the nearest tenth.

Answer 1

Therefore, the elevation of the car on the stretch of road, rounded to the nearest tenth, is approximately 29.7 meters.

Explanation:

To find the elevation of the car on a stretch of road that extends horizontally 125 meters, we can use trigonometry.

Given:

Angle of the road = 13°

Horizontal distance = 125 meters

We can use the tangent function to calculate the elevation:

tan(angle) = opposite / adjacent

In this case, the opposite side represents the elevation, and the adjacent side represents the horizontal distance.

Let's denote the elevation as "e". The equation becomes:

tan(13°) = e / 125

To solve for "e", we can rearrange the equation:

e = 125 * tan(13°)

Using a calculator, we can evaluate this expression:

e ≈ 125 * tan(13°) ≈ 29.7