Sure, I can help you with the remaining questions.
3) To find the mean (average) of the data, add up all the values and divide by the total number of values. Using the data provided, the sum of all the values is 141, and there are 14 values. Therefore, the mean is 141/14 = 10.1 (rounded to the nearest tenth).
4) To create a box plot of the data, we need to determine the minimum, maximum, median, first quartile (Q1), and third quartile (Q3).
Minimum: 6
Maximum: 20
Median: The median is the middle value when the data is arranged in ascending order. In this case, we have an even number of values, so we take the average of the two middle values. The two middle values are 10 and 11, so the median is (10 + 11)/2 = 10.5.
Q1 (First Quartile): The first quartile is the median of the lower half of the data. Since we have 14 values, the lower half consists of the first 7 values when arranged in ascending order. The values are 6, 7, 7, 8, 8, 10, and 10. The median of these values is (7 + 8)/2 = 7.5.
Q3 (Third Quartile): The third quartile is the median of the upper half of the data. Again, we have 14 values, so the upper half consists of the last 7 values when arranged in ascending order. The values are 10, 11, 11, 12, 12, 12, and 20. The median of these values is (11 + 12)/2 = 11.5.
Now, we can construct the box plot:
| (6) |
|_______|________|
(7.5) (10.1) (11.5)
The line in the middle represents the median (10.1), the left boundary represents Q1 (7.5), and the right boundary represents Q3 (11.5). The whiskers extend from the box to the minimum (6) and maximum (20) values.
5) The median of the data is 10.5.
6) The First Quartile (Q1) is 7.5.
7) The Third Quartile (Q3) is 11.5.
I hope this helps! Let me know if you have any further questions.