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Find the horizontal asymptotes: y=2x^2/3x^3 You must show your work and enter your answer below.

User Jeffrey
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1 Answer

3 votes

Answer:

y = 0

Explanation:

You want the horizontal asymptote of y=2x^2/3x^3.

Horizontal asymptote

Degree of numerator: 2

Degree of denominator: 3

When the degree of the denominator (3) is greater than the degree of the numerator (2), the horizontal asymptote is ...

y = 0

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Additional comment

This reduces to (2/3)(1/x). The value of 1/x approaches zero when the magnitude of x gets large.

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Find the horizontal asymptotes: y=2x^2/3x^3 You must show your work and enter your-example-1
User Keithernet
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