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Oatmeal is packaged in a cylindrical container, as shown in the diagram. The diameter of the container is 5.1centimeters and its height is 22 centimeters. To the nearest tenth of a cubic centimeter, what is the volume of the container?

User Ephrion
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1 Answer

4 votes

Answer:

approximately 449.6 cm^3.

Explanation:

To find the volume of the cylindrical container, we can use the formula for the volume of a cylinder:Volume = π * radius^2 * height

The given information states that the diameter of the container is 5.1 centimeters. We need to find the radius, which is half the diameter.Radius = Diameter / 2

Radius = 5.1 cm / 2

Radius ≈ 2.55 cmThe height of the container is given as 22 centimeters.Now, we can calculate the volume using the formula:Volume = π * radius^2 * height

Volume = π * (2.55 cm)^2 * 22 cmTo find the volume to the nearest tenth of a cubic centimeter, we can use an approximation of π as 3.14.Volume ≈ 3.14 * (2.55 cm)^2 * 22 cmCalculating the expression:Volume ≈ 3.14 * (6.5025 cm^2) * 22 cm

Volume ≈ 3.14 * 143.055 cm^3


Volume ≈ 449.6187 cm^3Rounding the volume to the nearest tenth of a cubic centimeter:Volume ≈ 449.6 cm^3Therefore, to the nearest tenth of a cubic centimeter, the volume of the cylindrical container is approximately 449.6 cm^3.

User Alokj
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