Answer:
In this case, the optimal solution occurs at X1 = 40 and X2 = 0, which gives a maximum value of Z = 200. This means that if you produce 40 units of X1 and 0 units of X2, you will achieve the highest possible value of Z.
Explanation:
aX1 + bX2 ≤ c
where a, b, and c are constants.
The first constraint, 1.5X1 + 2.5X2 ≤ 80, is already in standard form. The second constraint, 2X1 + 1.5X2 ≤ 70, can be rewritten in standard form as follows:
-2X1 - 1.5X2 ≤ -70
You can now write the problem in the following standard form:
Maximize Z = 5X1 + 4X2
Subject to:
1.5X1 + 2.5X2 ≤ 80
-2X1 - 1.5X2 ≤ -70
X1, X2 ≥ 0