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F(x)=(x-1)(x-2)(x-3)(x-4)(x-3)(x-2)(x-2)/[(x-2)(x-4)(x-2)]
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F(x)=(x-1)(x-2)(x-3)(x-4)(x-3)(x-2)(x-2)/[(x-2)(x-4)(x-2)]

User Rafareino
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1 Answer

4 votes

Answer:

Explanation:

(x-2)(x-2)(x-4)

User JustAndrei
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