To find the concentration of the potassium hydroxide (KOH) solution, you can use the concept of stoichiometry and the balanced chemical equation for the reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH).
The balanced equation for the reaction is:
H2SO4 + 2KOH -> K2SO4 + 2H2O
From the equation, you can see that the mole ratio between H2SO4 and KOH is 1:2. This means that for every mole of H2SO4, you need 2 moles of KOH.
Given that the volume of the H2SO4 solution is 22.20 cm^3 and its concentration is 0.045 moldm^-3, you can calculate the number of moles of H2SO4 using the formula:
Moles = Concentration × Volume
= 0.045 moldm^-3 × 22.20 cm^3
Now, since the mole ratio between H2SO4 and KOH is 1:2, the number of moles of KOH required will be twice the number of moles of H2SO4.
Moles of KOH = 2 × Moles of H2SO4
Next, you are given that 20 cm^3 of the KOH solution is required to neutralize the H2SO4 solution. Since you know the moles of KOH required, you can calculate its concentration using the formula:
Concentration = Moles / Volume
= (2 × Moles of H2SO4) / 20 cm^3
Now you can substitute the values and calculate the concentration of the KOH solution:
Concentration = (2 × 0.045 moldm^-3 × 22.20 cm^3) / 20 cm^3
Simplifying the expression:
Concentration = 0.099 moldm^-3
Therefore, the concentration of the potassium hydroxide (KOH) solution is approximately 0.099 moldm^-3.