Answer:
Explanation:
sinθ=-725cosθ=2425tanθ=-724cotθ=-247secθ=124cscθ=-17Explanation:Let the point P(x,y) be on a circle of radius r centered at the origin and P is on the terminal ray of θ. Let the angle α be the the nonreflex angle from the positive x-axis that is coterminal with θ.θ terminates in QIV, so for point P, x is positive and y is negative. α is negative..The line segments from (0,0) to (x,0) and to (0,y) form a right triangle with hypotenuse r and angle α between x and r. cosα=xr and sinα=yr.Since α and θ start and end in the same place, all of their trig functions are the same, so by finding the function values for α we find them for θ. You can say that since θ=α+2π, they are effectively the same angle; I will be using θ because that is what we're looking for.cosθ=xr. We are given that cosθ=2425. Therefore, x=24 and r=25.x, y, and r are the lengths of the two legs and the hypotenuse of a right triangle, respectively. Therefore, x2+y2=r2. Solving for y, y=±√r2−x2. We know the values of x and r, so we can find that y=±√252−242=±7. We know that y is negative so y=-7.sinθ=yr, so sinθ=-725tanθ=yx, so tanθ=-724cotθ=xy, so cotθ=24-7=-247secθ=1x, so secθ=124cscθ=1y, so cscθ=1-7=-17