Question

In circle J with the measure of minor arc HK= 90°, find m/HLK.

L
K
D
J.
H

Answer 1

45°

Explanation:

You want the measure of inscribed angle HLK, given that arc HK is 90°.

Inscribed angle

The measure of an inscribed angle is half the measure of the arc it subtends.

∠HLK = 1/2(arc HK) = 1/2(90°)

∠HLK = 45°

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