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How many total atoms are in 0. 440 g of P2O5

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First of all find moles of P2O5


\tt Moles = (given \: weight)/(molecular \: mass)


\tt Moles = (0.440)/(142)


\tt Moles = 0.003

Multiply it by avogadro number to find atoms:


\sf \: 0.003 * 6.023 * {10}^( - 23)


\sf \: 1.8 * {10}^( - 25)

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