111k views
1 vote
What type of reaction is depicted in the equation above?

What type of reaction is depicted in the equation above?-example-1

2 Answers

5 votes

Answer:

Beta decay

In beta decay, a neutron is converted into a proton and an electron. The electron is then fired out of the nucleus whilst the proton remains.

This means that the the neutron number decreases by 1, and the proton number increases by 1 (therefore the nucleon number remains unchanged).

User Lennox
by
7.8k points
3 votes

Answer:

Beta Decay

Step-by-step explanation:

Beta decay conserves the number of electrons and their associated neutrinos Since a proton or neutron has lepton number zero, β+ decay (a position, or antielectron) must be accompanied with an electron neutrino, while β− decay (an electron) must be accompanied by an electron antineutrino. An example of electron emission (β− decay) is the decay of C 14 into N14 with a half-life of about 5,730 years

In this form of decay, the original element becomes a new chemical element. This new element has an unchanged mass number A, but an atomic number Z that is increased by one.

User MotoRidingMelon
by
7.9k points

No related questions found