Answer:
F) 1, -1
Explanation:
You want the real solutions to |x|² +2|x| -3 = 0.
Solution
We can let z = |x|. Then the equation becomes ...
z² +2z -3 = 0
(z +3)(z -1) = 0 . . . . . factored
The solutions will be the values of z that make the factors zero:
z +3 = 0 ⇒ z = -3
z -1 = 0 ⇒ z = 1
Z = -3
Substituting our definition of z, we have ...
|x| = -3
The absolute value is never negative, so there are no values of x that satisfy this equation.
Z = 1
Substituting our definition of z, this is ...
|x| = 1
This is true for x = ±1.
The real solutions to the equation are 1, -1.