Question

Transform the standard form of the following quadratic function into vertex form and into intercept form.: f(x) = -3x ^2 - 6x + 24.

What is the vertex? What are the x-intercepts?

SHOW YOUR WORK CLEARLY

Answer 1

-3(x+1)^2+27

-3x^2 - 6x + 24

Explanation:
f(x) = -3x^2 - 6x + 24 is the base equation

the vertex form is: -3(x+1)^2+27

-3x^2 - 6x + 24

(x+1)^2 = x^2 + 2x + 1

-3(x^2 + 2x + 1) = -3x^2 - 6x - 3

( -3x^2 -6x - 3 ) + 24 = -3(x+1)^2+27

the intercept form is: -3x^2 - 6x + 24 ( nothing needs to be changed