Answer: 480 N is required to maintain the arrangement .
Step-by-step explanation:
Given, 320 N force is required to hold 2 protons in a particular arrangement .
Then the force required to keep 1 proton in a particular arrangement = 320/2
= 160 N
Then if a proton is replaced by an alpha particle , it is given that a alpha contains 2 protons , then we conclude that after replcament , the arrangement has 1 alpha and 1 proton = 3 protons
Then , the force exerted by 3 protons = 3×160 = 480 N
The force exerted by the arrangement , if one of the protons is replaced with alpha is 480 N