Answer:
Step 1:
UQH2 + 2 cyt c (Fe3+) → UQ + 2 cyt c (Fe2+)
This step involves the oxidation of UQH2 and reduction of cyt c (Fe3+). The net reaction involves a 2-electron transfer from UQH2 to cyt c (Fe3+).
The standard reduction potential for UQH2 to UQ is given as 0.06 V, and for cyt c (Fe3+) to cyt c (Fe2+) it is 0.254 V.
The net standard reduction potential for step 1 can be calculated as follows:
E°_net1 = E°(UQH2) - E°(cyt c (Fe3+))
E°_net1 = 0.06 V - 0.254 V
E°_net1 = -0.194 V
Step 2:
UQH2 + 2 cyt c (Fe3+) → UQH + 2 cyt c (Fe2+)
This step also involves the oxidation of UQH2 and reduction of cyt c (Fe3+). The net reaction involves a 2-electron transfer from UQH2 to cyt c (Fe3+).
The standard reduction potential for UQH2 to UQH is given as 0.19 V.
The net standard reduction potential for step 2 can be calculated as follows:
E°_net2 = E°(UQH2) - E°(cyt c (Fe3+))
E°_net2 = 0.19 V - 0.254 V
E°_net2 = -0.064 V
Total redox potential of Complex III:
To calculate the total redox potential, we sum up the net reduction potentials of step 1 and step 2:
E°_total = E°_net1 + E°_net2
E°_total = -0.194 V + (-0.064 V)
E°_total = -0.258 V
Now, let's calculate the free energy available for proton translocation assuming a 2-electron process for each complex.
The equation relating free energy change (ΔG) and standard reduction potential (E°) is given by:
ΔG = -nFΔE°
Where:
ΔG is the free energy change
n is the number of electrons transferred
F is Faraday's constant (96,485 C/mol)
ΔE° is the standard reduction potential
For a 2-electron process, n = 2.
ΔG1 = -2 * 96,485 C/mol * (-0.194 V)
ΔG1 = 37,508.12 J/mol
ΔG2 = -2 * 96,485 C/mol * (-0.064 V)
ΔG2 = 12,303.04 J/mol
Therefore, the free energy available for proton translocation for each complex is 37,508.12 J/mol for Complex III, step 1, and 12,303.04 J/mol for Complex III, step 2.
To calculate the moles of protons translocated, we can use the equation:
ΔG = nFΔp
Where:
ΔG is the free energy change in joules
n is the number of moles of protons
F is Faraday's constant (96,485 C/mol)
Δp is the potential difference finish up now