Answer:
sorry i apologize that for my ability it's difficult to provide a diagram but your diagram will expressed as follow. also in summary it represented through notation. below
For the given reaction:
2Ag⁺(aq) + Pb(s) → Pb²⁺(aq) + 2Ag(s)
The voltaic cell consists of the following components:
Anode: The electrode where oxidation occurs. In this case, the anode is the solid lead (Pb) electrode.
Cathode: The electrode where reduction occurs. In this case, the cathode is the solid silver (Ag) electrode.
Anode electrolyte: The electrolyte solution surrounding the anode. It contains silver ions (Ag⁺(aq)).
Cathode electrolyte: The electrolyte solution surrounding the cathode. It contains lead ions (Pb²⁺(aq)).
Salt bridge: A tube or pathway containing an electrolyte solution that connects the two electrolyte solutions, allowing ion flow and maintaining electrical neutrality.
Now, let's write the cell notation for the given reaction:
Anode: Pb(s) | Pb²⁺(aq)
Cathode: 2Ag⁺(aq) | Ag(s)
The cell notation represents the two half-cells separated by a vertical line. The anode is written on the left, and the cathode is written on the right. The single vertical line represents the phase boundary between the electrode and the electrolyte solution. The double line represents the salt bridge.
Therefore, the cell notation for the given reaction is:
Pb(s) | Pb²⁺(aq) || 2Ag⁺(aq) | Ag(s)