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Match the system of equations with the number of solutions.

y = 6z+8
y = 6x-4
y = 3x + 2
y + 3x = -7
4z - 2y = 10
2z-y = 5
4z + y = 8
y=-2z+8
No Solution

Match the system of equations with the number of solutions. y = 6z+8 y = 6x-4 y = 3x-example-1

1 Answer

3 votes

Answer:

Explanation:

The system of equations with no solution is:

y + 3x = -7

4z - 2y = 10

The system of equations with exactly one solution is:

y = 6z+8

y = 6x-4

y = 3x + 2

2z-y = 5

y=-2z+8

The system of equations with infinitely many solutions is:

4z + y = 8

User Ovidijus Parsiunas
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