Question

a gas in a sealed container has a pressure of 125 kPa at a temperature of 30.0 degrees C. If the pressure in the container is increased to 206 kPa, what is the new temperature?

Answer 1

226°C

Step-by-step explanation:

By using the gas equation,

P1V1/T1 = P2V2/T2

Let volume = x ml

Converting T1 to Kelvin scale, 30 C = 303K

Substituting the values,

`(125kPa . x)/(303K)` =
`(206kPa . x)/(T2)`

or, T2 = 499.344 K ≈ 226°C Ans.