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1 vote
6^{2} + b^{2} = 8^{2}

2 Answers

4 votes
It’s the Pythagorean theorem so first you do the exponents

36+ b^2 = 64


64-36=28
__
_/28

5.3~~ approximately
User Lee Baldwin
by
7.1k points
2 votes

Answer:

-{2√7} or {2√7}

Explanation:

1) Simplify the exponents 6^2 and 8^2 by multiplying 6*6=36 and 8*8=64.

2) Write an equation, 36+b^2=64

3) Subtract 36 from both sides, b^2=28

4) Apply a square root to both sides, √(b^2)=√(28)

5) Simplify the equation, b=-√(28) or b=√28

6) If you want, factor the square root by finding a factor that is a square number, -{√(4)*√7} or {√(4)*√7}; -{2√7} or {2√7}

User Manoj Tolagekar
by
8.3k points

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