Question

A wagon, Initially traveling at a constant 3.6 m/s, starts going down a hill that creates an acceleration of

1.6 m/s2. What is the wagon's velocity 4.8 s after it starts accelerating down the hill?

Answer 1

To determine the wagon's velocity 4.8 seconds after it starts accelerating down the hill, we can use the following kinematic equation:

v = u + at

where:
v is the final velocity,
u is the initial velocity,
a is the acceleration, and
t is the time.

Given:
u (initial velocity) = 3.6 m/s (constant velocity)
a (acceleration) = 1.6 m/s²
t (time) = 4.8 s

Using the equation and substituting the values, we have:

v = 3.6 m/s + (1.6 m/s²)(4.8 s)

v = 3.6 m/s + 7.68 m/s

Performing the addition:

v = 11.28 m/s

Therefore, the wagon's velocity 4.8 seconds after it starts accelerating down the hill is 11.28 m/s.