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Find the perimeter of a rectangle where the width is 2x^2 + 5x-4 and the length is 3x+2

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Answer:

The perimeter of the rectangle is P = 4x^2 + 16x - 4.

Explanation:

1. L = 3x + 2, W = 2x^2 + 5x - 4

2. P = 2(L + W)

3. P = 2((3x + 2) + (2x^2 + 5x - 4))

4. P = 2(2x^2 + 8x - 2)

5. P = 4x^2 + 16x - 4

User TheLittleNaruto
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