Final answer:
To stay at the same level on the graph, one must walk in a direction perpendicular to the gradient at the point. The gradient at the point (2, 1) is <-1, -1>, so a direction perpendicular to this could be <1, -1>.
Step-by-step explanation:
To find an x, y-direction you should walk in to stay at the same level on the graph of f(x, y) = y cos(πx) − x cos(πy) + 16, standing at the point (2, 1, 19), we must consider the level curves (contour lines) of this function. To remain at the same level, a person must move in a direction where the function's value does not change, which is tangent to the level curve passing through the point (2, 1).
Mathematically, this is equivalent to finding the gradient of f(x, y) and moving in a direction perpendicular to it. The gradient is a vector pointing in the direction of the steepest ascent on the graph. Therefore, to stay at the same level, you need to move in a direction orthogonal to the gradient since this represents no change in f(x, y)'s value.
Calculating the gradient at the point (2, 1), we get the vector:
grad f(2, 1) = \∇f(2, 1) = <−cos(π), −cos(2π)> = <−1, −1>.
To stay on the same level, you need to walk in a direction perpendicular to <−1, −1>. One such direction is <1, −1>, which means you should walk in a direction where you increase your x-coordinate by the same amount that you decrease your y-coordinate.