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Solve by substitution and elimination (make sure to check after every method)

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Solve by substitution and elimination (make sure to check after every method) SHOW-example-1
Solve by substitution and elimination (make sure to check after every method) SHOW-example-1
Solve by substitution and elimination (make sure to check after every method) SHOW-example-2
User Ben Kane
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2 Answers

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yes the answer above is correct
User Mkmitchell
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Answer:

In a substitution reaction an existing group on the substrate is removed and a new group takes its place. In an elimination reaction the group is simply removed and no new group comes to take its place and this usually results in a double or triple bond forming in the substrate instead.

Explanation:

User John Bachir
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