Question

What is the 10th term of the geometric sequence where a1 = 384 and a7 = 6?

0.75

3

6

1.5

Answer 1

(a) 0.75

Explanation:

You want the 10th term of the geometric sequence with a1 = 384 and a7 = 6.

N-th term

The equation for the n-th term can be written ...

an = a1·b^(n-1)

Using a1 = 384, we can find b from ...

a7 = 6 = 384·b^(7-1)

(6/384)^(1/6) = b

10th term

Then the 10th term is ...

a10 = 384·(6/384)^((10-1)/6) = 0.75

The 10th term of the sequence is 0.75.

<95141404393>