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What is the 10th term of the geometric sequence where a1 = 384 and a7 = 6?

0.75

3

6

1.5

User Toadead
by
8.6k points

1 Answer

2 votes

Answer:

(a) 0.75

Explanation:

You want the 10th term of the geometric sequence with a1 = 384 and a7 = 6.

N-th term

The equation for the n-th term can be written ...

an = a1·b^(n-1)

Using a1 = 384, we can find b from ...

a7 = 6 = 384·b^(7-1)

(6/384)^(1/6) = b

10th term

Then the 10th term is ...

a10 = 384·(6/384)^((10-1)/6) = 0.75

The 10th term of the sequence is 0.75.

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What is the 10th term of the geometric sequence where a1 = 384 and a7 = 6? 0.75 3 6 1.5-example-1
User Mantas Astra
by
7.7k points

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