Question

Log5
`(1)/(25)`

Answer 1

`\Huge \boxed{\text{Answer = -2}}`

Explanation:

To solve this logarithmic expression, we need to ask ourselves: what power of 5 gives us the fraction
`(1)/(25)`? In other words, we need to solve the equation:

`\large 5^(x) = (1)/(25)`

We can simplify
`(1)/(25)` to
`5^(-2)`, so our equation becomes:

`5^(x) = 5^(-2)`

Now we may find
`x` by applying the rule "if two powers with the same base are equal, then their exponents must be equal." As a result, we have:

`x = -2`

So the value of the logarithmic expression
`\log_5 (1)/(25)` is -2.

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