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Assuming ideal solution behavior, what is the boiling point of a solution of 9. 04 g of I2 in 75. 5 g of benzene, assuming the I2is nonvolatile?

User Oillio
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1 Answer

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Tb=Kb(m)(#ions)
m= moles/kg
molar mass I2 = 254g
moles= 9.04 x 1 mole/254g = 0.0356
m= 0.0356/0.0755 = 0.472
2.53 (chart)
(2.53)(0.472)(2) = 2.39
2.39 + 80.1 = 82.49 degrees c
User Ale
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