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The area of the shaded sector is shown. Find the radius of $\odot M$ . Round your answer to the nearest hundredth.

A circle with center at point M. Two points K and J are marked on the circle such that the measure of the angle corresponding to minor arc K J, at the center, is 89 degrees. Point L is marked on major arc K J. Area of minor sector is equal to 12.36 square meters.

The radius is about ____ meters.

The area of the shaded sector is shown. Find the radius of $\odot M$ . Round your-example-1
User Nitsuj
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1 Answer

2 votes

Answer:

3.99 m

Explanation:

Area of circle = π r ²

Area of sector = (angle / 360) X area of circle

Length of arc = (angle / 360) X circumference of circle

using area of sector:

12.36 = (89/360) X π r ²

π r ² = (12.36) ÷(89/360)

= 12.36 X (360/89)

r² = [ 12.36 X (360/89)] ÷ π

r = √[12.36 X (360/89) ÷ π]

= 3.99 m to nearest hundredth

User Mashiro
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