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calculate the heat released when 0.300 mol of steam at 158 degrees c is cooled to the ice at -83 degrees c.

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Final answer:

To calculate the total amount of heat released, we can use the equation Q = mcΔT. First, we need to calculate the heat released when the steam is cooled from 158 degrees C to 0 degrees C. Next, we calculate the heat released when the water changes from liquid at 0 degrees C to ice at -83 degrees C.

Step-by-step explanation:

To calculate the total amount of heat released, we can use the equation:

Q = mcΔT

Where Q is the heat released, m is the mass of the substance, c is the specific heat capacity, and ΔT is the temperature change.

First, we need to calculate the heat released when the steam is cooled from 158 degrees C to 0 degrees C:

Q₁ = (0.300 mol) × (18.02 g/mol) × (2.03 J/g°C) × (158 - 0)°C

Next, we calculate the heat released when the water changes from liquid at 0 degrees C to ice at -83 degrees C:

Q₂ = (0.300 mol) × (18.02 g/mol) × (2.03 J/g°C) × (0 - (-83))°C

The total heat released is the sum of Q₁ and Q₂:

Q = Q₁ + Q₂

Substituting the values and solving the equation will give us the total amount of heat released.

User Orville Jackson
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