Question

FIFTY POINT QUESTION PLEASE HELP

Approximate the slant height of a cone with a volume of approximately 28.2 ft and a height of 2 ft. Use 3.14 for π and round to the nearest tenth

Answer 1

We can use the formula for the volume of a cone to solve for the radius of the cone, and then use the Pythagorean theorem to find the slant height.

The formula for the volume of a cone is:

V = (1/3)πr^2h

Substituting the given values, we get:

28.2 = (1/3)(3.14)r^2(2)

Simplifying and solving for r, we get:

r^2 = (28.2 / 3.14) / (2/3.14) = 4.5

r ≈ 2.12 (rounded to two decimal places)

Now, we can use the Pythagorean theorem to find the slant height (l):

l^2 = r^2 + h^2

l^2 = 2.12^2 + 2^2

l^2 ≈ 8.5

l ≈ 2.92 (rounded to two decimal places)

Therefore, the approximate slant height of the cone is 2.92 feet.

Answer 2

We can use the formula for the volume of a cone to solve for the radius of the cone, and then use the Pythagorean theorem to find the slant height.

The formula for the volume of a cone is:

V = (1/3)πr^2h

Substituting the given values, we get:

28.2 = (1/3)(3.14)r^2(2)

Simplifying and solving for r, we get:

r^2 = (28.2 / 3.14) / (2/3.14) = 4.5

r ≈ 2.12 (rounded to two decimal places)

Now, we can use the Pythagorean theorem to find the slant height (l):

l^2 = r^2 + h^2

l^2 = 2.12^2 + 2^2

l^2 ≈ 8.5

l ≈ 2.92 (rounded to two decimal places)

Therefore, the approximate slant height of the cone is 2.92 feet.