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4 votes
The test point (2, 1) makes the inequality 3x + 2y ≤ 2 \) true.

Select one:
O True
O False

User Ping Li
by
8.1k points

2 Answers

7 votes

Answer

O False

Explanation

Let's plug in each co-ordinate into the inequality:


\sf{3x+2y\leqslant2}

I plug in 2 for x and 1 for y:


\sf{3(2)+2(1)\leqslant2}

Simplify


\sf{6+2\leqslant2}


\sf{8\leqslant2}

Hence, the (2,1) doesn't make the inequality true, so the statement is false.

User Arthur Zennig
by
9.0k points
3 votes
To determine whether the test point (2, 1) makes the inequality 3x + 2y ≤ 2 true, we substitute the values of x and y into the inequality and evaluate it.

For the test point (2, 1):
3(2) + 2(1) ≤ 2
6 + 2 ≤ 2
8 ≤ 2

Since 8 is not less than or equal to 2, the inequality is false when using the test point (2, 1).

Therefore, the answer is:
False

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