Question

water is added to 275 mL of a 2.55 M potassium hydroxide solution until the final volume is 485 mL, what will the molarity of the diluted potassium hydroxide solution be?

Answer 1

The molarity of the diluted potassium hydroxide solution can be calculated using the formula:

M1V1 = M2V2

where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

Plugging in the given values, we get:

M1 = 2.55 M

V1 = 275 mL

V2 = 485 mL

We need to find M2.

M1V1 = M2V2

2.55 M x 275 mL = M2 x 485 mL

M2 = (2.55 M x 275 mL) / 485 mL

M2 = 1.45 M

Therefore, the molarity of the diluted potassium hydroxide solution is 1.45 M.