Answer:
The given matrix equation can be written as:
[2 3; 1 2] * [x; y] = [5; 4]
Multiplying the matrices on the left side of the equation gives us the system of equations:
2x + 3y = 5 x + 2y = 4
To solve for x and y using matrices, we can use the inverse matrix method. First, we need to find the inverse of the coefficient matrix [2 3; 1 2]. The inverse of a 2x2 matrix [a b; c d] can be calculated using the formula: (1/(ad-bc)) * [d -b; -c a].
Let’s apply this formula to our coefficient matrix:
The determinant of [2 3; 1 2] is (22) - (31) = 1. Since the determinant is not equal to zero, the inverse of the matrix exists and can be calculated as:
(1/1) * [2 -3; -1 2] = [2 -3; -1 2]
Now we can use this inverse matrix to solve for x and y. Multiplying both sides of our matrix equation by the inverse matrix gives us:
[2 -3; -1 2] * [2x + 3y; x + 2y] = [2 -3; -1 2] * [5; 4]
Solving this equation gives us:
[x; y] = [-7; 6]
So, the solution to the system of equations is x = -7 and y = 6.