Answer:
Given:
Mass of glucose (m) = 281.1 g
Molar mass of glucose (MM) = 180.2 g/mol
Volume of solution (V) = 325 mL
First, let's convert the volume of the solution from milliliters (mL) to liters (L):
V = 325 mL = 325/1000 L = 0.325 L
Next, we can calculate the mass of glucose in the solution using its molar mass and the given mass:
moles of glucose (n) = m / MM
n = 281.1 g / 180.2 g/mol
Now, we need to calculate the mass percent by volume:
mass percent by volume = (mass of glucose / mass of solution) x 100
mass of solution = mass of glucose
mass percent by volume = (mass of glucose / mass of solution) x 100
= (n x MM / V) x 100
Substituting the values:
mass percent by volume = ((281.1 g / 180.2 g/mol) x 180.2 g/mol) / 0.325 L) x 100
Calculating this expression will give us the mass percent by volume of glucose in the solution.